Ответ:
разложим по формуле разности квадратов:
[tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex]
[tex]((3 {x}^{2} - 5x - 2) - ( {x}^{2} + x - 6)) \times ((3 {x}^{2} - 5x - 2) + ( {x}^{2} + x - 6)) = 0 \\ (3 {x}^{2} - 5x - 2 - {x}^{2} - x + 6) \times (3 {x}^{2} - 5x - 2 + {x}^{2} + x - 6) = 0 \\ (2 {x}^{2} - 6x + 4)(4 {x}^{2} - 4x - 8) = 0 \\ ( {x}^{2} - 3x + 2)( {x}^{2} - x - 2) = 0 \\ \\ {x}^{2} - 3x + 2 = 0 \\ D = 9 - 8 = 1 \\ x1 = \frac{3 + 1}{2} = 2 \\ x2 = 1 \\ \\ {x}^{2} - x - 2 = 0 \\ D = 1 + 8 = 9 \\ x3= \frac{1 + 3}{2} = 2 \\ x4 = - 1[/tex]
Ответ: -1; 1; 2.
